Type Alias ExtractFunction<T>

ExtractFunction<T>: T extends AnyFunction<infer P, infer R>
? ((...args: P) => R)
: never

Extract the function signature from a composite type T.

It works with interact of functions, but not on function overloads and union.

Type Parameters

T extends AnyFunction

Note

does not work with function overloads.

import type { ExtractFunction } from 'type-plus'

type R = ExtractFunction<{
  () => void
  a: 1
}> // () => void